India beat England by four wickets in first ODI at Nagpur; Shubman Gill scores 87
India beat England by four wickets in the first ODI at the VCA Stadium, Nagpur, on 6 February 2025, with Shubman Gill named Player of the Match for his 87.
Summary
India defeated England by four wickets with 68 balls to spare in the first of three ODIs at the Vidarbha Cricket Association Stadium, Jamtha, Nagpur, on 6 February 2025. England were bowled out for 248, with Ravindra Jadeja taking 3 for 26 and debutant Harshit Rana 3 for 53. India reached 251 for 6 in 38.4 overs; Shubman Gill made 87 and was Player of the Match, supported by Shreyas Iyer's 59 and Axar Patel's 52. India took a 1-0 lead in the series.
Key facts
- Date and venue
- 6 February 2025, VCA Stadium, Jamtha, Nagpur
- Result
- India won by 4 wickets (68 balls left); lead series 1-0
- Scores
- England 248; India 251/6 (38.4 overs)
- Player of the Match
- Shubman Gill (87 off 96)
- Bowling
- Ravindra Jadeja 3/26; Harshit Rana 3/53 on ODI debut
Practice MCQs 2 questions
Who was named Player of the Match in the first India–England ODI at Nagpur on 6 February 2025?
Show answer
Correct answer: A — Shubman Gill
Shubman Gill was Player of the Match for his 87 off 96 balls as India chased down 249 to win by four wickets.
Which Indian bowler took 3 for 53 on his ODI debut against England at Nagpur on 6 February 2025?
Show answer
Correct answer: B — Harshit Rana
Harshit Rana took 3 for 53 in seven overs on his ODI debut, including the wickets of Ben Duckett, Harry Brook and Liam Livingstone.