Density, Pressure & Depth
Mechanical Properties of Fluids
1. Fluids – Density & Relative Density
- Fluid : material which has the property to flow → liquids + gases.
- Liquid : no fixed shape, but fixed volume. Gas : neither fixed shape nor fixed volume.
- Density = mass per unit volume ; unit kg/m³. Water ≈ 1000 kg/m³ = 1 g/cm³ (1 litre ≈ 1 kg).
- 1 cm³ = 10⁻⁶ m³ ; 1 litre = 10⁻³ m³.
- A ratio ⇒ no unit. e.g. specific gravity 7.2 ⇒ ρ = 7200 kg/m³ = 7.2 g/cm³.
2. Density of a Mixture
- Liquids mixed together (total volume = sum of volumes) ; use m = ρV :
- Equal volumes : ρeq = ρ₁ + ρ₂ + …n (arithmetic mean).
- Equal masses : ρeq = n1/ρ₁ + 1/ρ₂ + … (harmonic mean).
e.g. 1 : 2 by volume ⇒ (ρ₁ + 2ρ₂)/3 ; 1 : 2 by mass ⇒ 3ρ₁ρ₂/(ρ₂ + 2ρ₁).
3. Pressure & Force due to Pressure
- Pressure : force per unit area on a surface, due to collisions of the fluid molecules with it. Unit N/m² = Pascal (Pa) ; a scalar.
(F = PA when P is uniform over the area ; F = ∫P dA when P varies)
- Force due to pressure is always perpendicular to the surface and is a push (compressive) force.
Atmospheric pressure :
- Due to the weight of the air column above a point ; measured by a barometer. Decreases with altitude.
- At the interface of air and liquid, pressure is continuous ⇒ at the free surface P = P₀.
4. Variation of Pressure with Depth
- Fluid at rest ; liquid incompressible (ρ = constant). Pressure varies due to gravity, acceleration and rotation of the vessel.
- Thin layer (area A, thickness dx, mass dm = ρA dx) in equilibrium :
P₂A = P₁A + (ρA dx)g ⇒ dP = ρg dx ⇒ ∫AB dP = ∫₀h ρg dx
- Pressure increases linearly as we move down.
- Holds between any two points of the same liquid at rest, along any path (h = vertical depth of B below A).
- All points at the same horizontal level in the same continuous liquid at rest have the same pressure — independent of the shape of the vessel.
5. Pressure in a Vertically Accelerating Vessel
| Motion of vessel | geff | PB − PA |
|---|---|---|
| Acceleration a upward | g + a | ρ(g + a)h |
| Acceleration a downward | g − a | ρ(g − a)h |
| Free fall (a = g, down) | 0 | 0 |
(B is at depth h below A ; in free fall the pressure is the same everywhere in the liquid.)
Layers, Vessel Walls & Pascal
6. Layered Liquids & U-tubes
- Immiscible layers in an open vessel : add ρgh layer by layer.
- U-tube rule : equate pressures at the level of the lower interface, where both points lie in the same liquid ⇒ ρ₁h₁ = ρ₂h₂ (heights measured above that level).
Sol. At the interface level (both points in 2ρ) : P₀ + ρgh₁ = P₀ + 2ρg(h₁ − h) ⇒ h = h₁/2 (lighter-liquid side higher).
7. Force on the Bottom & Walls of a Vessel
- Ignore P₀. At the bottom (depth h) pressure is uniform = ρgh ⇒ F₁ = ρgh × (base area).
- On slant walls pressure is variable ⇒ F₂ = ∫P dA (always ⊥ wall).
- FBD of the liquid : weight W (down), F₁ from bottom (up), net vertical force F₂ from the walls ⇒ F₁ ± F₂ = W.
| Vessel (filled, height h) | Result |
|---|---|
| Cylinder | F₁ = W ; wall forces horizontal, cancel ⇒ net 0 |
| Wider at top | W > F₁ ; liquid pushes walls down with W − F₁ |
| Narrower at top | W < F₁ ; liquid pushes walls up with F₁ − W |
e.g. frustum, bottom radius R, top 2R : W = 73πR²ρgh, F₁ = πR²ρgh ⇒ walls pushed down by 43πR²ρgh. Top R/2, bottom R : W = 712πR²ρgh ⇒ walls pushed up by 512πR²ρgh.
8. Hydrostatic Paradox
- Vessels of different shapes, same base area A, filled to the same height h with the same liquid :
but the weights differ : W₂ > W₁ > W₃
- Force on the base depends only on h and A, not on the amount (weight) of liquid.
- Weighing machine reads the total weight (vessel + liquid), not the force on the base — the liquid also pushes on the walls.
9. Force on a Vertical Wall
- Strip of area l dx at depth x (cube of side l, filled) : P = ρgx
F = ∫₀l (ρgx)(l dx) = ρgl³2 = mg2 (bottom : ρgl · l² = mg)
PC = pressure at the centroid C of the (projected) wall area — valid because P varies linearly with depth.
- Centre of pressure (line of action of F) lies below the centroid : at depth 2h3 for a rectangular wall (torque about the bottom edge = F·h/3 = ρgbh³/6).
- Layered liquids : apply the rule separately to the part of the wall in contact with each layer.
- Common wall between liquids ρ₂ > ρ₁ (same h, width a) : net force = (ρ₂ − ρ₁)gah²/2 towards the lighter side.
- Curved wall : liquid in equilibrium ⇒ force on the curved wall = force on the flat face it closes, e.g. half-cylinder (radius R, height h) : F = (ρgh/2)(2Rh) = ρgRh².
Sol. Upper part : (ρg h2)(ah) = ½ρgah². Lower part : centre pressure = ρgh + 2ρgh2 = 2ρgh ⇒ 2ρgah².
Total = 52ρgah² ; bottom : (ρgh + 2ρgh)a² = 3ρgha².
10. Pascal's Law & Hydraulic Lift
- Pascal's law : a pressure change applied at any point of a confined incompressible fluid is transmitted undiminished to every point of the fluid and to the walls of the container.
P₁ = P₂ ⇒ F₁A₁ = F₂A₂
- Small force on the small piston lifts a large load on the big piston — force multiplier.
- Force is multiplied, work is not : A₁d₁ = A₂d₂ ⇒ F₁d₁ = F₂d₂.
- Pistons at different levels (lower one at depth h below the other) : FlowAlow = FhighAhigh + ρgh.
Barometer, Accelerated & Rotating Liquids
11. Gauge Pressure & Manometer
- Gauge pressure = pressure measured with respect to atmospheric pressure (P itself is the absolute pressure).
- May be positive, negative or zero : P = 1.5 × 10⁵ Pa ⇒ +0.5 × 10⁵ Pa ; P = 0.4 × 10⁵ Pa ⇒ −0.6 × 10⁵ Pa.
- At depth h in an open liquid : Pgauge = ρgh.
Manometer (U-tube measuring gas pressure) :
- Several liquids : start from one end, add ρgh going down and subtract going up, until the other end ; e.g. specific gravity 4, h = 6 cm ⇒ Pgauge = 2400 Pa.
12. Barometer & Faulty Barometer
- Tube closed at the top, filled with liquid and inverted in a trough ; space above the column is (nearly) vacuum, P = 0.
- Mercury (13.6 g/cm³) : h ≈ 76 cm ; water : h ≈ 10.3 m (too tall ⇒ mercury is used).
- P₀ ≈ 10⁵ Pa ≈ 76 cm of Hg. In mercury 5 cm below the surface ⇒ 81 cm of Hg ; 2 cm above the outside level inside a column ⇒ 74 cm of Hg.
Faulty barometer (air trapped at the top) :
- Reading h is less than the true value P₀/ρg.
- Trapped gas at constant temperature : P₁V₁ = P₂V₂ ; uniform tube ⇒ V = A × (length of air column).
- Air column closed by a mercury pellet of length l : open end down ⇒ P = P₀ − l ; open end up ⇒ P = P₀ + l ; horizontal ⇒ P = P₀ (in cm of Hg).
13. Pressure in a Horizontally Accelerated Liquid
- Horizontal column (length l, area A) between B (rear) and A (front), acceleration a :
PBA − PAA = (ρAl)a
- Gravity : pressure increases along mg ⇒ ΔP = ρgh (vertical distance h).
- Acceleration : pressure increases along the pseudo force, i.e. opposite to a ⇒ ΔP = ρal (horizontal distance l).
14. Free Surface of an Accelerated Liquid
- Open vessel with horizontal acceleration a : at steady state the free surface is inclined.
A, B on the free surface (P₀) ; C below A and behind B : P₀ + ρgy = P₀ + ρax
- Surface rises towards the rear ; it is perpendicular to geff.
- U-tube (horizontal arm l) accelerated along the arm : h = alg, rear arm higher.
Vessel moving up a smooth incline (θ) with acceleration a :
(α = angle of the surface with the incline ; per unit mass : a + g sinθ along the incline, g cosθ normal to it.)
Closed vessel completely filled :
- Closed vessel (length l, height h), completely filled, acceleration a towards the front : Prear top − Pfront top = ρal ; Pfront bottom − Pfront top = ρgh ; Prear bottom − Pfront top = ρgh + ρal (rear bottom maximum, front top minimum).
- General acceleration : pressure is maximum at the corner farthest along geff = g − a and minimum at the opposite corner. Cube of side l, a = a₁î + a₂ĵ + a₃k̂ (ĵ up) : Pmax − Pmin = ρ(g + a₂)l + ρa₁l + ρa₃l.
15. Pressure in a Rotating Liquid
- Horizontal tube of liquid rotating with angular velocity ω about a vertical axis through O.
Element (dm = ρA dx) needs centripetal force dm ω²x from the pressure difference :
(P + dP)A − PA = (ρA dx)ω²x ⇒ ∫P₀PA dP = ∫₀l ρω²x dx
(P₀ = pressure on the axis ; A at distance l from the axis.)
- Pressure increases away from the axis (l₂ > l₁ measured from the axis).
- Rotating U-tube, arms at distances r₁ and r₂ from the axis : h = ω²(r₂² − r₁²)2g, the farther arm higher (e.g. 2l and l ⇒ 3ω²l²/2g).
- Tube closed at both ends, full of liquid of mass m, rotated about one end : force on the far end = ½ρω²L²A = mω²L/2 (= net centripetal force on the liquid).
Rotating Vessel, Archimedes & Floating
16. Rotating Vessel – Paraboloid Surface
Sol. A (centre) and B (wall) at P₀ ; C at A's level below B : P₀ + ρgh = P₀ + ½ρω²R² ⇒ h = ω²R²/2g.
Any surface point (x, y) from A : ρgy = ½ρω²x² ⇒ y = ω²x²/2g — a parabola (surface is a paraboloid of revolution).
e.g. R = 5 cm, 2 rev/s (ω = 4π rad/s) ⇒ h ≈ 2 cm.
17. Archimedes' Principle & Buoyant Force
- A body immersed in a fluid, fully or partially, experiences an upward buoyant force equal to the weight of the fluid displaced by it.
Spring balance : 5 kg in air, 3 kg immersed ; the overflow water weighs 2 kg = loss in weight.
- ρ → density of the liquid ; V → immersed volume of the body.
- Accelerating frame (lift / vessel) : Fb = ρ V geff.
- Mass of the body M = σV₀ (σ = density of body, V₀ = total volume).
18. Buoyancy from Pressure
- Buoyant force = net force exerted by the liquid on the body due to pressure.
Side forces cancel (F₂ = F₄). Fnet = F₃ − F₁ = [P₀ + ρg(h + h₁)]A − [P₀ + ρgh₁]A = ρ(hA)g
- Independent of P₀ and of the depth h₁ of the body.
- Any shape : replace the body by liquid of the same shape ; that liquid is in equilibrium, so the net pressure force on it = its weight = ρVg.
- Trick : Fb = ρVg is a short-cut to the net pressure force ; conversely Fbottom − Ftop = Fb gives an unknown pressure force on one surface.
19. Sinking, Floating & Free Float
| Density | Forces (fully immersed) | Result |
|---|---|---|
| σ < ρ (wood) | Fb > mg | moves up, floats partly immersed |
| σ = ρ | Fb = mg | stays at rest anywhere inside |
| σ > ρ (iron) | Fb < mg | sinks |
- Free float (only Fb and mg act) : ρVg = σV₀g
20. Floating Results & Apparent Weight
- Extra load to just submerge a floating body : mg = ρ(V₀ − V)g (extra buoyancy of the part above the liquid).
- Boat (base area A) sinks further by Δh when load m is added : m = ρAΔh.
- Hollow body : displaced volume uses the outer volume, weight uses the volume of material : ρVdisp = σVmaterial (e.g. shell of radii R, 2R floating half-immersed ⇒ σ = 4ρ/7).
- Body across two liquids (length h₁ in ρ₁, h₂ in ρ₂, h₁ + h₂ = h) :
Apparent weight :
- The body pushes the liquid down with Fb (Newton's 3rd law) ⇒ weighing machine under the beaker reads more by Fb ; total of both readings is unchanged.
21. Vertical Oscillation of a Floating Block
- Block (height h, area A, density σ) floats in liquid ρ with immersed depth h₁ : ρh₁ = σh.
Push down by x : Fnet = extra Fb = (ρAg)x (restoring) ⇒ SHM with k = ρAg
(Viscous drag and liquid motion neglected ; block stays partly immersed.)
Buoyancy Cases, Flow & Continuity
22. Force on Curved Surfaces
- Treat the curved part as one face of a closed body : Fcurved (net, vertical) and Fflat differ by the buoyant force.
- Cone (base area πR², height H) hung vertex down, base at depth h : Fcurved = ρgπR²(h + H3) upward — independent of the cone's density.
- Sphere (radius R) with top at depth h, force on the lower hemisphere (flat face at depth h + R) :
23. Two Balls & Two-Liquid Floating
- Two balls (same V) joined by a taut string, in equilibrium inside liquid ρ : upper σ₂ < ρ < σ₁ lower.
- Block floating across two liquids : the upper liquid presses only on the top face, the lower only on the bottom face ; Fbottom − Ftop = Fb1 + Fb2 = mg.
24. Buoyancy in an Accelerating Vessel
- Vessel with horizontal acceleration a : in its frame a pseudo force σVa acts backward ; the liquid gives an extra buoyant force ρVa along a (replace g by a).
- W.r.t. the vessel : heavier body (iron) moves backward, lighter body (wood) moves forward.
Ball (σ > ρ) on a string in a closed, filled vessel : T sinθ = (σ − ρ)Va , T cosθ = (σ − ρ)Vg
(String lies along geff ; for a light ball σ < ρ it tilts forward.)
25. Ball Dropped into a Liquid
- Ball (density σ < ρ) released from height h above the surface ; no loss of speed on entry, no viscosity.
In air : v₀² = 2gh. In liquid (upward retardation) : ρVg − σVg = σVa ⇒ a = (ρσ − 1)g
Work–energy : σVg(h + s) − ρVgs = 0 ⇒
e.g. σ = 800, ρ = 1000 kg/m³ ⇒ a = g/4, s = 4h.
26. Melting of Floating Ice
Sol. Floating : displaced volume V = σV₀/ρ. Melting conserves mass : melt-water volume V′ = σV₀/ρ = V ⇒ level unchanged.
With a stone : while floating it displaces ms/ρ ; after melting it sinks and displaces only ms/σs < ms/ρ ⇒ level falls.
- Similarly : a steel block on a floating wooden block thrown into the water ⇒ level decreases.
27. Centre of Buoyancy (COB)
- Fb acts at the centre of buoyancy = centroid of the displaced volume.
- Weight acts at the COM. If COB and COM are not on one vertical line, Fb and mg form a couple ⇒ the body rotates.
Wood–iron rod (equal volumes) fully immersed : COB at the geometric centre, COM towards iron ⇒ iron end goes down.
- Rod hinged at the bottom (length l, density σ < ρ, liquid depth h) : immersed length L = h secθ ; torque about the hinge ⇒ ρL² = σl² :
(Valid when h < l√(σ/ρ) ; otherwise the rod stays vertical.)
28. Fluid Dynamics – Streamlines & Types of Flow
- Streamlines : curves that are, at every instant, tangent to the velocity of the flow at each point.
Laminar (streamline) flow :
- Streamlines do not change with time (steady flow) ; every particle through a given point follows the same path.
Turbulent flow :
- Streamlines change with time ; particles through a point do not follow the same path (eddies form).
29. Reynolds Number
- Dimensionless ratio of inertial force to viscous force ; decides whether pipe flow is laminar or turbulent.
ρ → density of liquid, v → speed, d → diameter of tube, η → coefficient of viscosity (Pa·s), Q → volume flow rate (v = 4Q/πd²)
- Re < ≈ 2000 : laminar ; Re > ≈ 3000 : turbulent ; in between : unstable (transition). Exact limits vary slightly from book to book.
- Large ρ, v, d ⇒ turbulence more likely ; large η ⇒ laminar.
- For the same Q : Re ∝ 1/d (wider tube ⇒ smaller Re).
30. Flow Rate & Equation of Continuity
- Pipe of area A, speed v : in time dt the liquid crossing a section fills length v dt.
Units : m³/s (or L/s) and kg/s. Water : 1 L/s ↔ 1 kg/s ; 1 cm³/s ↔ 1 g/s.
- Mass is conserved (steady flow, no leak) : mass in per second = mass out per second, at any section or junction.
- Incompressible liquid (ρ constant) :
- Narrower section ⇒ faster flow (v ∝ 1/A ∝ 1/r²) ; streamlines crowd where speed is large.
- Junction : Av = A₁v₁ + A₂v₂ + … (volume in = volume out).
Bernoulli, Siphon, Efflux & Lift
31. Bernoulli's Equation
- For steady, streamline flow of an incompressible, non-viscous liquid, the total energy per unit volume is the same at all points of a streamline.
Energy of a liquid element (mass dm, volume dV) :
| Energy | Total | Per unit mass | Per unit volume |
|---|---|---|---|
| Kinetic | ½(dm)v² | ½v² | ½ρv² |
| Potential | (dm)gh | gh | ρgh |
| Pressure | P dV | P/ρ | P |
(Pressure energy per unit volume equals the pressure P itself.)
together with continuity : A₁v₁ = A₂v₂
- Horizontal tube : where speed is more, pressure is less.
- Uniform tube ⇒ same v everywhere ⇒ Plower − Pupper = ρgh (as in statics).
- Note : P = P₀ + ρgh holds only for a liquid at rest ; for moving liquid use Bernoulli.
- Point open to atmosphere (free jet / open end) ⇒ P = P₀.
- Valve in a horizontal pipe : closed reading P₁, open P₂ ⇒ v = √(2(P₁ − P₂)/ρ).
32. Venturi Meter
- Device to measure the volume flow rate in a pipe.
Continuity : v₂ = A₁v₁/A₂ ; Bernoulli (same height) : P₁ − P₂ = ½ρ(v₂² − v₁²) = ½ρv₁²A₁² − A₂²A₂²
Manometer tubes : P₁ − P₂ = ρgh ⇒ v₁ = A₂ √(2gh)√(A₁² − A₂²)
- Wide part : v less, P more ; throat : v more, P less.
Sol. vB = 2v ⇒ ΔP = ½ρ(4v² − v²) = 32ρv² ⇒ 700 = 1500 v² ⇒ v ≈ 0.683 m/s
Q = (40 × 10⁻⁴)(0.683) ≈ 2.73 × 10⁻³ m³/s (≈ 2.73 L/s).
33. Siphon
- Uniform tube draining a vessel : A = inlet (depth h₁), B = highest point (h₂ above the surface), C = open outlet (h₃ below A).
- Uniform tube ⇒ vA = vB = vC = v ; C open to air ⇒ PC = P₀.
- Liquid at A is moving, so PA ≠ P₀ + ρgh₁ ; Bernoulli with C :
- Flow condition : PB > 0 ⇒ P₀ > ρg(h₁ + h₂ + h₃) ; C must be below the free surface.
- Free surface → C (tube area ≪ vessel area) : v = √(2g(h₁ + h₃)).
34. Speed of Efflux (Torricelli) & Range
- Small hole (area a) in the wall of a vessel (area A), depth h below the free surface.
Continuity : surface speed vs = av/A ; Bernoulli : P₀ + ½ρvs² + ρgh = P₀ + ½ρv²
- Same speed as a body falling freely through h.
Range on the ground (hole at height h₁ = H − h) :
time of fall t = √(2h₁/g) ⇒ R = vt = √(2gh)·√(2h₁/g)
- R is maximum at h = h₁ = H/2 ; Rmax = H.
- Same R if h and h₁ are interchanged (hole at depth d from the top and at height d from the bottom).
Two liquid layers (ρ₁, h₁ over ρ₂, h₂), hole at the bottom :
- Piston pushing liquid out of a nozzle : Ppiston − P₀ = ½ρ(v₂² − v₁²) ⇒ force F = (Ppiston − P₀)A₁.
- A falling stream narrows (RC = R(H/(H + h))1/4 at distance h below the tap) ; a rising jet slows and widens.
35. Thrust Force
- Liquid flowing out with speed v (relative to the vessel) pushes the vessel the opposite way.
- v = √(2gh) (a ≪ A). Smooth ground : acceleration = Fth/M ; rough ground : on the verge of sliding when Fth = μMg (M = vessel + liquid).
- Light vessel, hole at the bottom : μmin = 2ρaghρAhg = 2aA.
36. Time to Empty a Tank
A(−dhdt) = a√(2gh) ⇒ ∫Hh dh√h = −aA√(2g) ∫₀t dt
- T ∝ √H : the lower half takes longer ; t2nd half/t1st half = 1/(√2 − 1) = √2 + 1 (e.g. 200 s → ≈ 483 s).
- Steady level with inflow Q (volume per second) : Q = a√(2gh) ⇒ h = Q²2ga².
37. Dynamic Lift (Bernoulli in Air)
- Air above the wing moves faster (v₂ > v₁) ⇒ pressure above is less ⇒ net upward force.
- Take-off when lift = Mg.
- Wind of speed v over a roof (still air inside) : ΔP = ½ρv² ⇒ force ½ρv²A upward (roof blown off).
Viscosity & Terminal Velocity
38. Viscosity & Viscous Force
- Viscosity : property of a fluid by which it resists flow — opposes relative motion between its layers and of bodies moving through it (honey : high, water : low).
Newton's law of viscosity :
- η = coefficient of viscosity ; (−) : the force opposes relative motion — faster layer dragged back, slower layer dragged forward.
| System | Unit of η |
|---|---|
| SI | Pa·s (= N s/m²) = 1 decapoise = 1 poiseuille |
| CGS | poise ; 1 poise = 0.1 Pa·s (10 poise = 1 Pa·s) |
Water (room temperature) : η ≈ 1 mPa·s = 10−3 Pa·s (= 0.01 poise) ; dimensions [ML⁻¹T⁻¹]
Linear velocity profile (e.g. river of depth h) :
- v varies linearly from 0 at the bed to v at the top ⇒ dvdy = Δvh :
- No-slip condition : the fluid layer touching a solid surface moves with that surface (layer at the river bed is at rest).
| Viscous force | Kinetic friction |
|---|---|
| Fv ∝ A (area of contact) | independent of area |
| Fv ∝ Δv and ∝ 1/h | independent of velocity |
| independent of normal force | fk = μN ∝ N |
39. Viscous Force between Two Plates
- Plates of area A separated by a liquid layer of thickness h : only the relative velocity matters.
| Top plate | Bottom plate | vrel | Fv |
|---|---|---|---|
| v → | at rest | v | ηAv/h |
| 3v → | v → | 2v | 2ηAv/h |
| 3v → | ← v | 4v | 4ηAv/h |
- Constant velocity ⇒ applied force = total viscous drag, e.g. boat (area A) on a river of depth D : F = ηAv₀/D ; block sliding down an oiled incline : mg sinθ = ηAv/h.
- Plate between two others : add the drags from both liquid layers.
- Cylinder (radius R, length l, mass m) falling in a pipe with lubricant gap r ≪ R : mg = η(2πRl)v/r ⇒ v = mgr2πηRl.
40. Stokes' Law & Terminal Velocity
- Sphere of radius r moving with velocity v through a liquid of viscosity η (small speed, streamline flow) :
Terminal velocity :
Fnet = mg − Fb − Fv ; Fv grows with v until Fnet = 0 ⇒ constant terminal speed :
6πηrv = (σ − ρ)43πr³g
- σ > ρ (steel ball in water) : moves down ; σ < ρ (air bubble in water) : vT negative ⇒ rises with terminal speed.
- Same r, ρ, η : vT ∝ (σ − ρ). At terminal speed, viscous force = mg − Fb.
- Height of fall for which the speed does not change on entering the liquid : √(2gh) = vT ⇒ h ∝ r⁴.
Graphs (released from rest) :
- Acceleration falls from g(1 − ρ/σ) to zero ; speed rises and approaches vT asymptotically.
Rate of heat production at terminal velocity :
vT ∝ r² ⇒ P ∝ r⁵ ; P ∝ vT5/2
41. Merging or Breaking of Drops
Volume conservation : 43πR³ = N · 43πr³
Sol. R = 81/3r = 2r ; vT ∝ r² ⇒ v′ = 4 × 10 = 40 cm/s. In general v′ = N2/3v ; a sphere broken into 27 drops ⇒ each drop's vT is 1/9 of the original.
Surface Tension & Summary
42. Surface Tension & Soap Film
- Surface tension : tendency of a liquid surface at rest to shrink to the minimum possible area — it behaves like a stretched elastic membrane.
- e.g. spherical drops (minimum area), brush hair clinging together out of water, insects walking on water, capillary rise ; soap / detergents decrease it (cleaning).
- Surface tension decreases with increase in temperature and with impurities like soap.
- Force acts along (tangent to) the surface, perpendicular to the line, and is attractive :
T in N/m (= J/m², energy per unit area) — fixed for a liquid at a given temperature.
- A soap film has two free surfaces :
43. Excess Pressure inside Drops & Bubbles
Soap bubble (two surfaces) :
Hemisphere in equilibrium : PπR² = P₀πR² + T(2πR)·2
Liquid drop (one surface) :
Air bubble at depth h in a liquid (one surface) :
| Case | Free surfaces | Pin − Pout |
|---|---|---|
| Soap bubble in air | 2 | 4T/R |
| Liquid drop in air | 1 | 2T/R |
| Air bubble in liquid | 1 | 2T/R |
- Smaller radius ⇒ larger excess pressure (higher on the concave side) ⇒ two connected bubbles : air flows from the smaller to the larger.
- Bubble of radius R inside one of 2R : Pouter = P₀ + 2T/R, Pinner = P₀ + 6T/R.
- Work to expand a soap bubble R₁ → R₂ : W = 8πT(R₂² − R₁²) (R → 2R : 24πR²T).
- Drop of radius R broken into N drops : ΔE = 4πR²T(N1/3 − 1) increase ⇒ the liquid cools ; merging drops releases energy (heats).
Sol. The film is concave towards the smaller (higher-pressure) bubble : 4TR₁ − 4TR₂ = 4Tr ⇒ r = R₁R₂R₂ − R₁
44. Formula Summary
| Quantity | Formula |
|---|---|
| Density ; mixture | ρ = m/V ; ρeq = ΣρiVi/ΣVi |
| Pressure at depth h | P = P₀ + ρgh |
| Vertical acceleration a | ΔP = ρ(g ± a)h ; free fall ΔP = 0 |
| Horizontal acceleration a | Prear − Pfront = ρal ; tanα = a/g |
| Up an incline (θ) | tanα = (a + g sinθ)/(g cosθ) |
| Rotation ω | ΔP = ½ρω²(l₂² − l₁²) ; h = ω²R²/2g ; y = ω²x²/2g |
| Force on base / wall | F = ρgh × base area ; Fwall = Pcentroid × projected area ; rectangle ρgbh²/2 at depth 2h/3 |
| Hydraulic lift | F₁/A₁ = F₂/A₂ |
| Barometer | P₀ = ρgh (76 cm Hg ≈ 10.3 m water) ; faulty : P = P₀ − ρgh |
| Buoyant force | Fb = ρVimmgeff |
| Free float ; two liquids | Vimm = (σ/ρ)V₀ ; σh = ρ₁h₁ + ρ₂h₂ |
| Two balls on a string | σ₁ + σ₂ = 2ρ ; T = (σ₁ − ρ)Vg |
| Floating block (SHM) | T = 2π√(σh/ρg) |
| Ball dropped into liquid | smax = σh/(ρ − σ) |
| Reynolds number | Re = ρvd/η = 4ρQ/πηd |
| Flow rate ; continuity | Q = Av ; dm/dt = ρAv ; A₁v₁ = A₂v₂ |
| Bernoulli | P + ½ρv² + ρgh = constant |
| Venturi meter | Q = A₁A₂√(2gh/(A₁² − A₂²)) |
| Efflux ; range | v = √(2gh) ; R = 2√(h h₁) ; Rmax = H at h = H/2 |
| Two-layer efflux | v = √(2g(ρ₁h₁ + ρ₂h₂)/ρ₂) |
| Thrust | Fth = ρav² = 2ρagh |
| Time to empty | T = (A/a)√(2H/g) |
| Dynamic lift | (P₁ − P₂)A = ½ρ(v₂² − v₁²)A |
| Viscous force | F = ηA dv/dy ; plates F = ηAvrel/h |
| Stokes ; terminal velocity | F = 6πηrv ; vT = 2r²g(σ − ρ)/9η |
| Heat rate at vT | P = 6πηrvT² ∝ r⁵ |
| N drops → 1 drop | R = N1/3r ; vT → N2/3vT |
| Surface tension | F = Tl (film : 2Tl) ; energy = T × area |
| Excess pressure | soap bubble 4T/R ; drop / air bubble 2T/R |
ρ = liquid density, σ = body density, η = viscosity, T = surface tension (in the SHM row, T = time period).
Key Points :
- Pressure force is always ⊥ to the surface ; F = PA (uniform P), F = ∫P dA (variable P).
- Same level + same continuous liquid at rest ⇒ same pressure (any vessel shape) ; in U-tubes equate pressures at the lower interface level.
- Pressure increases along g, opposite to the acceleration and away from the rotation axis.
- Force on the base = ρghA, independent of the liquid's weight ; a weighing scale reads the total weight.
- Gauge pressure = P − Patm (can be negative). Hydraulic lift multiplies force, not work.
- Fb uses the liquid density and the immersed volume ; it acts at the centroid of the displaced volume.
- Floating ice melting : level unchanged ; ice with a stone : level falls. In an accelerating vessel light bodies move along a, heavy ones opposite.
- Laminar below Re ≈ 2000, turbulent above ≈ 3000 (limits vary slightly by book).
- Bernoulli : steady, streamline, incompressible, non-viscous flow ; moving liquid ⇒ do not use P = P₀ + ρgh ; open end ⇒ P = P₀. Faster flow ⇒ lower pressure.
- Viscous force depends on area and relative velocity, not on normal force ; no-slip at solid surfaces ; 1 Pa·s = 10 poise, water η ≈ 10⁻³ Pa·s.
- vT ∝ r² ; σ < ρ ⇒ the body rises (air bubble).
- Surface tension falls with temperature and soap ; smaller bubble ⇒ larger pressure ; breaking drops cools, merging heats.