Properties and Definition of Solutions & Henry's Law Concepts
Solutions
1. Properties and Definition of Solutions
- Solution properties reflect properties of each component mixed.
- Particle size: < 1 nanometer (10−9 m).
- Composition: One solvent and one or more solutes (e.g., water + sugar + lemon + salt).
- Solute: The component that dissolves.
- Solvent: The component that does the dissolving.
- The physical state (phase) of a solution is determined by the solvent.
2. Identifying Solute and Solvent
- Criteria 1 (Different Phases): The component which has the same phase as the final solution is the solvent.
- Criteria 2 (Same Phase): The component present in the greater amount is the solvent.
3. Components of a Solution
- A solution consists of two primary components: the solute and the solvent.
- Solvent: The component present in a larger quantity (greater number of moles).
- Solute: The component dissolved in the solvent, present in a smaller quantity.
Examples of Solute and Solvent Identification :
| Solution | Solute | Solvent |
|---|---|---|
| Tea | Sugar, Tea powder | Water |
| Shikanji | Lemon juice, Sugar | Water |
| Air (O2, N2, CO2) | O2, CO2 | N2 |
| Vinegar | Acetic acid | Water |
4. Types of Solution by Physical State
- Gaseous solutions
- Liquid solutions
- Solid solutions
Gaseous Solutions :
| Solute | Solvent | Example |
|---|---|---|
| Gas | Gas | O2 + N2 |
| Liquid | Gas | Chloroform in N2 |
| Solid | Gas | Camphor in N2 |
Liquid Solutions :
| Solute | Solvent | Example |
|---|---|---|
| Gas | Liquid | O2 in water |
| Liquid | Liquid | Ethanol in water |
| Solid | Liquid | Glucose in water |
Solid Solutions :
| Solute | Solvent | Example |
|---|---|---|
| Gas | Solid | H2 in Pd |
| Liquid | Solid | Amalgam of Hg with Na |
| Solid | Solid | Cu in Au |
5. Solubility of Gas in Liquid
- Solubility: The maximum amount of gas dissolved in a solvent per litre at a particular temperature.
6. Henry's Law Concepts
- The partial pressure of a gas in the vapour phase (p) is proportional to the mole fraction of the gas in the solution (χ).
- p = KHχ.
- Key characteristics:
- Different gases have different KH values at the same temperature.
- The value of KH increases with an increase in temperature.
- KH is a function of the nature of the gas.
- For a given pressure, a lower value of KH implies higher solubility of the gas in the liquid.
7. Henry's Law & Solubility Trends
- For gases, more solubility = less KH (Henry's Law constant).
- KH depends on the nature of the gas. Polar gases (e.g., SO2) have higher solubility and lower KH values compared to non-polar gases (e.g., H2).
- In a Pgas vs Xgas graph, a steeper slope represents a higher KH value and thus lower solubility.
8. Vapour Pressure of Pure Liquid
- Molecules in the bulk:
- Are stable.
- Have lower energy.
- Are in equilibrium.
- Molecules at the surface:
- Are not in equilibrium.
- Are less stable.
- Have high energy.
- Equilibrium process: Liq ⇌ Vap, where (rate)evap = (rate)cond.
- Vapour Pressure (V.P.): The pressure exerted by vapours on the surface of the liquid and the walls of the container at a given temperature (T).
9. Effect of Temperature on Vapour Pressure
- Vapour pressure of a pure liquid depends only on temperature.
- In general, as Temperature (T) increases, Vapour Pressure (V.P.) increases.
- The process Liq ⇌ Vap is endothermic (ΔH = positive).
- For an endothermic reaction, the equilibrium constant (Kp) increases with an increase in temperature. Since Kp = V.P. for this equilibrium, V.P. increases.
- The relationship between V.P. and T is exponential.
Molecular Basis (Maxwell-Boltzmann Distribution) & Raoult's Law
10. Molecular Basis (Maxwell-Boltzmann Distribution)
- E0 is the minimum energy required for molecules to leave the liquid surface.
- The Maxwell-Boltzmann distribution shows that increasing the temperature increases the fraction of molecules having energy greater than or equal to E0.
- Consequently, the rate of evaporation increases, leading to an increase in vapour pressure.
- Note: While PV = nRT, for vapour pressure P ∝ T is incorrect. The dependence is exponential, not linear.
11. Intermolecular Forces and Vapour Pressure
- Vapour pressure is inversely proportional to the strength of intermolecular forces.
- Intermolecular forces ↑ ⇒ V.P. ↓
- For two liquids A and B at the same temperature, if their intermolecular forces are f1 and f2 respectively:
- If f1 > f2, then (V.P.)B > (V.P.)A.
12. Strength of Intermolecular Forces
Order of force strength:
- Examples:
- Ionic: Na+:::Cl−
- Ion-Dipole: Na+---H2O
- Hydrogen Bond: H2O---H2O---H2O
- Dipole-Dipole: Acetone (CH3-C(=O)CH3 interaction)
- Dipole-Induced Dipole: H2O---Br-Br (δ+ δ-)
- General order: Hydrogen Bonding > Dipole-Dipole > Vander Waal attraction.
- (Force of attraction)Polar > (Force of attraction)Non-polar.
- For non-polar molecules: Larger size/surface area (higher molecular weight) leads to stronger forces of attraction.
13. Vapour Pressure of a Solution (Non-volatile Solute)
- When a non-volatile solute is added to a volatile solvent, the vapour pressure of the solution (Ps) is lower than that of the pure solvent (P°).
- Reasons for decrease in V.P.:
- Number of solvent particles per unit surface area is less in the solution.
- Due to solute-solvent interactions.
14. Raoult's Law
- The partial vapour pressure of each component in a solution is proportional to its mole fraction in the solution.
15. Vapour Pressure of a Solution of Two Volatile Liquids
- For a solution of two miscible, volatile liquids A and B:
PB = P°B XB
PT = PA + PB = P°A XA + P°B XB
PT = total vapour pressure, P°A/P°B = vapour pressure of pure components, XA/XB = mole fractions in the solution.
16. PT in Terms of Single Mole Fraction
In terms of XA :
PT = P°B + XA (P°A − P°B)
In terms of XB :
PT = P°A + XB (P°B − P°A)
17. Composition of Vapour Phase
- For a liquid mixture, the vapour phase composition is determined by the partial pressures of components:
- Partial pressure of A (PA) = P°A XA
- Partial pressure of B (PB) = P°B XB
- Total Vapour Pressure (PT) = PA + PB
- Ratio of vapour mole fractions:
XA = mole fraction of A in liquid phase; YA = mole fraction of A in vapour phase.
18. Vapour Pressure of Binary Solutions
- For a solution of two volatile components 1 and 2, where x1 and y1 are mole fractions in liquid and vapour phase respectively, the relationship follows a linear plot for 1/x1 vs 1/y1:
Distillation of Ideal Solutions & Immiscible Volatile Liquids
19. Distillation of Ideal Solutions
- Distillation is a process to separate components of a mixture based on differences in volatility.
- If A is more volatile than B (P°A > P°B), the vapour will be richer in A than the liquid phase.
- By repeatedly condensing the vapour (which is richer in the more volatile component) and re-boiling, the liquid becomes progressively purer in the more volatile component.
Pressure-Composition Curve :
- The P-xA graph displays three regions: liquid (L) at the top, vapour (V) at the bottom, and a liquid-vapour equilibrium region (L+V) in between.
- A zig-zag path on the graph illustrates the distillation process: moving from the liquid composition (xA) to the vapour composition (yA) in the L+V region, which then becomes the liquid composition (x'A) for the next stage.
20. Ideal Solution: Fractional Distillation
- For the nth container in a fractional distillation process, the mole fraction of component A in the vapour phase (YA,n) is related to the initial mole fraction in the liquid phase (XA,1) by:
Where A is the more volatile component (P°A > P°B). As n → ∞, the vapour becomes enriched with the more volatile component (YA,n → 1).
21. Composition of Vapour Phase
- When a liquid mixture evaporates, the composition of the first drop of vapour formed (YA, YB) relates to the liquid composition (XA, XB) as:
22. Composition of Last Drop of Liquid
- As evaporation proceeds, the composition of the remaining liquid changes. For the last drop of liquid remaining (X'A, X'B), the vapour pressure is determined by its composition:
- The relation between the final vapour composition and the final liquid composition (X'A) follows the same principle:
23. Immiscible Volatile Liquids
- When two liquids are immiscible, they do not mix.
- The total vapor pressure is the sum of the pure vapor pressures of the individual components:
- The mole fraction of components in the vapor phase is given by:
24. Vapor Phase Composition (Immiscible)
- The ratio of moles of A (nA) to moles of B (nB) in the vapor phase is:
- In terms of weights (WA, WB) and molar masses (MA, MB):
WA, WB = weight of A and B in the vapor phase.
25. Ideal Solutions
- An ideal solution is formed when similar interactions are replaced by the same type of interaction.
- Condition: A–B interaction = A–A and B–B interaction.
- Example: Hexane + Heptane.
ΔVmix = 0
ΔGmix < 0
ΔSmix > 0
- ΔHmix = 0 because energy required for bond breaking is equal to energy released during bond formation.
- ΔVmix = 0 for A–A + B–B → A–B (e.g., 10 + 10 = 20).
- ΔGmix < 0 since mixing occurs spontaneously.
- ΔSmix > 0 because A–A + B–B → 2A–B increases randomness (symmetrical to unsymmetrical).
26. Raoult's Law Graph (Ideal)
- Assuming A is more volatile: P°A > P°B.
27. Examples of Ideal Solutions
- Hexane + Heptane
- Benzene + Toluene
- Ethyl bromide + Ethyl Iodide
- Chlorobenzene + Bromobenzene
Non-Ideal Solutions (Positive Deviation)
28. Non-Ideal Solutions (Positive Deviation)
- Characteristics:
ΔVmix > 0
ΔSmix > 0
ΔGmix < 0
- Graph behavior: The total vapour pressure curve lies above the straight line ideal Raoult's law behavior.
- PT > P°A XA + P°B XB
29. Examples of Positive Deviation
- Ethanol + Cyclohexane
- Ethanol + water or Methanol + water
- Ethanol + Acetone
- CCl4 + Benzene or CCl4 + Toluene
- CCl4 + CHCl3
- CCl4 + Methanol
- Benzene + Acetone
- Acetone + CS2
- Acetaldehyde + CS2
30. Negative Deviation from Raoult's Law
- Occurs when weaker solvent-solvent (A-A, B-B) interactions are replaced by stronger solute-solvent (A-B) interactions.
- Condition: Interaction A-B > A-A and B-B interactions.
- PT < PA°xA + PB°xB.
ΔVmix < 0
ΔSmix > 0
ΔGmix < 0
31. Graph: Negative Deviation
- The total vapour pressure (PT) curve lies below the ideal line (dashed).
32. Examples of Negative Deviation
- CHCl3 + CH3COCH3 (Acetone)
- CHCl3 + C6H6 (Benzene)
- CHCl3 + C2H5OC2H5 (Diethylether)
- H2O + HCl
- H2O + HNO3
- CH3COCH3 + Aniline
- Phenol + Aniline
33. Chloroform and Acetone Mixture
- Components: CHCl3 (Dipole-Dipole) and CH3COCH3 (Dipole-Dipole).
- The mixture forms Hydrogen Bonds (H.B).
- Interaction strength: H.B > Dipole-Dipole.
34. Non-Ideal Solutions
- The main reason for deviation from ideal behavior in non-ideal solutions is the difference in intermolecular forces between the solute and solvent (A-B interaction) compared to pure components (A-A and B-B interactions).
- Positive Deviation : Occurs when the A-B attraction is weaker than the A-A and B-B attractions (A-B attraction < A-A, B-B).
- Negative Deviation : Occurs when the A-B attraction is stronger than the A-A and B-B attractions (A-B attraction > A-A, B-B).
35. Pressure-Composition Curves for Non-Ideal Solutions
- Ideal Solution: Shows a linear or standard convex curve connecting P°B and P°A.
- Negative Deviation:
- Weak (-)ve deviation: Curve lies slightly below the ideal dashed line.
- Strong (-)ve deviation: Curve lies significantly below the ideal dashed line.
- Positive Deviation:
- Weak (+)ve deviation: Curve lies above the ideal dashed line.
- Strong (+)ve deviation: Curve exhibits a peak where XA = YA.
36. Azeotropic Mixture
- A binary solution containing two volatile liquids where the liquid and vapour phases have the same composition.
- A boiling liquid mixture at the azeotropic composition produces vapour with the exact same composition as the liquid.
- Distillation cannot separate the two liquids in an azeotropic mixture because the condensate retains the same composition as the original mixture.
37. Minimum Boiling Azeotrope
- These azeotropes are formed by solutions showing large positive deviation from Raoult's Law.
- The boiling point of the solution is lower than the boiling point of either pure component.
- Example shown: Water and Ethanol. The curve shows a maximum vapour pressure point at approximately 0.95 ethanol and 0.05 water.
38. Maximum Boiling Azeotrope
- These azeotropes are formed by solutions which show negative deviation from Raoult's Law.
- The boiling point of the azeotropic mixture is more than that of either individual component.
Colligative Properties & Ebullioscopic Constant (Kb)
39. Colligative Properties
- Properties of a solution that depend only on the number of solute particles and not on their nature.
- Conditions:
- Solute must be non-volatile.
- Solution must be dilute.
40. Relative Lowering of Vapour Pressure (RLVP)
- Vapour pressure of solution (Ps) = P° × Xsolvent
- Relative Lowering of Vapour Pressure (RLVP) formula:
Where: P° = v.p. of pure solvent, Ps = v.p. of solution, W = weight, M = molar mass.
Alternative Form :
- Dividing by Xsolvent gives an exact form (useful when Ps is given): P° − PsPs = nsolutensolvent = Wsolute / MsoluteWsolvent / Msolvent
41. Comparison of RLVP
- RLVP ∝ Xsolute.
- Since Xsolute = nsolutensolute + nsolvent, for a fixed mass of solvent and equal masses of solutes, a smaller molar mass (Msolute) results in more moles (nsolute) and thus a higher RLVP.
42. Ostwald–Walker Experiment
- This experiment is used to determine the Relative Lowering of Vapour Pressure (RLVP).
- Dry air is passed sequentially through a solution, then pure solvent, and finally a U-tube containing an anhydrous dehydrating agent (CaCl2).
W1 = weight loss in solution container ; W2 = weight loss in solvent container.
Ps = Vapour pressure of solution ; P° = Vapour pressure of pure solvent.
43. Elevation in Boiling Point
- Vapour pressure of a solution containing a non-volatile solute is lower than that of the pure solvent.
- To reach atmospheric pressure (1 atm), the solution requires more heat, thus increasing its boiling point.
- This elevation is a colligative property.
Tb = B.P of solvent ; Tb' = B.P of solution 1 ; Tb'' = B.P of solution 2.
44. Ebullioscopic Constant (Kb)
- The boiling point elevation (ΔTb) is proportional to molality (m):
- Kb (Ebullioscopic Constant / Molal boiling point elevation constant) is a property of the solvent only.
- Relationship for Kb:
M = molar mass of solvent ; Tb = boiling point of solvent ; ΔHvap = heat of vaporisation of solvent.
- Since Kb ∝ Tb2ΔHvap:
- (ΔHvap)H2O ≫ (ΔHvap)Benzene (due to H-bonding vs Vander Waal forces).
- Consequently, (Kb)H2O < (Kb)Benzene.
45. Depression in Freezing Point
- Freezing point: The temperature at which the first crystal of ice separates and the solid phase is in dynamic equilibrium with the liquid phase.
- Condition: Freezing point is the temperature where the vapour pressure of the liquid phase equals the vapour pressure of the solid phase.
- Only the solvent freezes.
46. Depression in Freezing Point
- Freezing point itself is not a colligative property; however, the depression in freezing point (ΔTF) is a colligative property.
- Graphically, the freezing point corresponds to the temperature where the vapour pressure of the liquid solvent/solution intersects with the vapour pressure of the solid (frozen) phase.
- As solute concentration increases, the vapour pressure of the solution decreases, leading to a shift in the freezing point intersection to lower temperatures (TF° > TF' > TF'').
- Entropy relationships at equilibrium (solvent ⇌ ice): ΔG = ΔH − TΔS. At equilibrium ΔG = 0, so TF = ΔHfusΔS.
- Since TF ∝ 1ΔS and ΔS1 < ΔS2 < ΔS3 (entropy differences between solution phases and ice), it follows that (TF)solvent > (TF)soln1 > (TF)soln2.
Cryoscopic Constant (KF) & Osmotic Pressure (π)
47. Cryoscopic Constant (KF)
- The depression in freezing point is directly proportional to the molality (m) of the solution:
- KF is the cryoscopic constant or molal depression in freezing point constant. It is a characteristic property of the solvent only.
- Formula for KF:
Where M = molar mass of solvent, R = gas constant, TF = freezing point of solvent, ΔHfus = heat of fusion of solvent.
48. Concept of Ice Separation
- For the freezing process: ΔTF = KF ⋅ m.
- As molality (m) increases, the depression in freezing point (ΔTF) increases, causing the freezing point (F.P.) of the solution to decrease.
- Key Concept: During the cooling of a solution, the temperature until which the solution is being cooled is considered the freezing point of the remaining liquid solution.
49. Molal Depression and Elevation Constants
Kf = M R Tf2ΔHfus = M R TfΔSfus
where M = molar mass of solvent (kg), R = gas constant, Tb = boiling point, Tf = freezing point, ΔH = enthalpy of vaporization/fusion, ΔS = entropy of vaporization/fusion.
- Derived from ΔG = ΔH - TΔS. At freezing point (F.P.), ΔG = 0, so ΔHfus = TfΔSfus ⇒ ΔSfus = ΔHfusTf.
50. Osmotic Pressure
- Semipermeable membrane: Artificial (Cu2Fe(CN)6) or Natural (animal bladder).
- Osmosis: Movement of solvent molecules through a semipermeable membrane.
- In terms of solvent concentration: High solvent conc. → Low solvent conc.
- In terms of solution concentration: Low solute conc. → High solute conc.
51. Osmotic Pressure (π)
- Osmotic pressure is the extra pressure applied on the more concentrated solution side to stop the process of osmosis.
- It can also be measured by the hydrostatic pressure generated by the height (h) of the liquid column.
where h = height of liquid column, ρ = density, g = acceleration due to gravity.
- At equilibrium: (rate)solvent → solution = (rate)solution → solvent.
52. Reverse Osmosis
- When the pressure applied on the solution side (π') is greater than the osmotic pressure (π), the solvent flows from the solution side to the solvent side.
53. Calculation of Osmotic Pressure
- C = concentration (molarity), R = gas constant, T = temperature.
- Depending on units:
- If π is in atm: R = 0.082 atm L / K-mol
- If π is in Pa or N/m²: R = 8.314 J / K-mol
- Standard conversion: 1 atm = 1.013 × 105 N/m².
54. Hypertonic, Hypotonic and Isotonic Solutions
- For two solutions (1 and 2) with concentrations C1, C2 and temperatures T1, T2:
If T1 = T2, then C1 = C2
- If πsoln 1 > πsoln 2:
- Soln 1 is Hypertonic.
- Soln 2 is Hypotonic.
- At the same temperature: C1 > C2.
55. Resultant Osmotic Pressure of Mixed Solutions
- When two solutions of the same substance with different osmotic pressures (π1, π2) and volumes (V1, V2) are mixed:
56. Van't Hoff Factor (i)
- Due to association or dissociation of solute particles, the observed colligative property differs from the theoretical (calculated) colligative property.
- For any solute: i = McalMobs
Colligative Properties with Van't Hoff Factor
57. Colligative Properties with Van't Hoff Factor
- i) ΔTb = i Kb m
- ii) ΔTf = i Kf m
- iii) π = i CRT
- iv) RLVP = i nsolutei nsolute + nsolvent ≈ i nsolutensolvent
58. Dissociation
- Reaction: An ⇌ nA
- If α is the degree of dissociation:
n = number of particles the solute dissociates into.
59. Association
- Reaction: nA ⇌ An
- If β is the degree of association:
n = number of particles associating together.
- Example of association: CH3COOH (non-polar solvent).
- Reaction: 2CH3COOH ⇌ (CH3COOH)2
- [DIAGRAM: Dimerization of acetic acid via two hydrogen bonds between carboxylic acid groups.]
60. Non-Electrolytes
- For solutes like glucose, sucrose, or urea:
- Here, (C.P.)calculated = (C.P.)observed.
61. Vapour Pressure of Electrolyte Solutions
- For an aqueous solution of an electrolyte, the lowering of vapour pressure is calculated using the effective number of particles.
Where P° is vapour pressure of pure solvent, Ps is vapour pressure of solution, and χsolute is mole fraction of solute.
62. Relative Lowering of Vapour Pressure & Solubility
- For a salt with solubility S, dissolving as: XY₂₍ₛ₎ ⇌ X₍ₐq₎ + 2Y₍ₐq₎
- Number of solute particles formed = S + 2S = 3S
where S = solubility of the salt
63. Quick Formula Revision
| Quantity | Formula |
|---|---|
| Clausius–Clapeyron | log(P2/P1) = (ΔHvap/2.303R)(1/T1 − 1/T2) |
| Raoult's law (non-volatile solute) | Ps = P° Xsolvent |
| RLVP | (P° − Ps)/P° = Xsolute ; (P° − Ps)/Ps = nsolute/nsolvent |
| Two volatile liquids | PT = P°AXA + P°BXB = P°B + XA(P°A − P°B) |
| Vapour composition | YA = P°AXA/PT ; YA/(1 − YA) = (P°A/P°B) XA/(1 − XA) |
| PT from vapour composition | 1/PT = YA/P°A + YB/P°B |
| n-stage distillation | YA,n/(1 − YA,n) = (P°A/P°B)n XA,1/(1 − XA,1) |
| Immiscible liquids | PT = P°A + P°B ; WA/WB = P°AMA/(P°BMB) |
| Ostwald–Walker | (P° − Ps)/P° = W2/(W1 + W2) |
| Elevation in B.P. | ΔTb = iKbm ; Kb = MRTb2/(1000 ΔHvap) (M in g mol−1) |
| Depression in F.P. | ΔTf = iKfm ; Kf = MRTf2/(1000 ΔHfus) |
| Osmotic pressure | π = iCRT ; π = hρg ; mixing: π = (π1V1 + π2V2)/(V1 + V2) |
| van't Hoff factor | i = observed C.P./calculated C.P. = Mnormal/Mobserved |
| Dissociation / association | i = 1 + (n − 1)α ; i = 1 − (1 − 1/n)β |
Key Points :
- V.P. of a pure liquid depends only on temperature and rises exponentially with T; stronger intermolecular forces mean lower V.P.
- In the vapour, the more volatile component is always richer than in the liquid; repeated distillation enriches it further.
- Ideal solution: ΔHmix = 0, ΔVmix = 0, ΔSmix > 0, ΔGmix < 0 (e.g. benzene + toluene, hexane + heptane).
- Positive deviation (A–B weaker): ΔHmix > 0, ΔVmix > 0, higher V.P., minimum boiling azeotrope (ethanol + water).
- Negative deviation (A–B stronger): ΔHmix < 0, ΔVmix < 0, lower V.P., maximum boiling azeotrope (HNO3 + water, CHCl3 + acetone).
- Azeotropes boil with the same composition in liquid and vapour, so they cannot be separated by fractional distillation.
- Colligative properties depend only on the number of solute particles; Kb and Kf depend only on the solvent.
- On cooling a solution below its freezing point, only pure solvent separates as ice; the remaining solution freezes at the temperature it is cooled to.
- Isotonic solutions have equal iC at the same temperature; solvent flows from lower to higher iC (reverse osmosis when applied pressure > π).
- Electrolytes have i > 1, non-electrolytes i = 1, and acids that dimerise in benzene (acetic, benzoic) have i < 1.